[Pramāṇa](https://indike.org/pramana/) › [Studies](https://indike.org/pramana/ins) › [Science, technology and education](https://indike.org/pramana/ins.science) › [Mathematics in Ancient and Medieval India](https://indike.org/pramana/ins.science.bag-1979) › c8.s3.46 # Mathematics in Ancient and Medieval India c8.s3.46 Mathematics in Ancient and Medieval India c8.s3.46 - **Language:** English ### [c8.s3.46](https://indike.org/pramana/ins.science.bag-1979.c8.s3.46) \*Case ii\* ) Putting p = 3, we obtain as before from ( 6 ) and ( 8 ) $a₁ = 1, a₃ = - 1, a₅ = 5, a₂ = a₄ = a₆ = 0$ From (6), $2f (n) & = 1/n - 1/(n³) + 5/(n⁵) - (5²)/(n⁷) + / & = (n² + 4)/(n(n² + 5))$ $Hence f (n + 1) = ((n + 1)²4 + 1)/((n + 12) \[ (n + 1)² + 4 + 1 \])$ - [Previous: c8.s3.45](https://indike.org/pramana/ins.science.bag-1979.c8.s3.45) - [Next: c8.s3.47](https://indike.org/pramana/ins.science.bag-1979.c8.s3.47) - [Up: c8.s3](https://indike.org/pramana/ins.science.bag-1979.c8.s3) --- Source: [https://indike.org/pramana/ins.science.bag-1979.c8.s3.46](https://indike.org/pramana/ins.science.bag-1979.c8.s3.46) · Pramāṇa