唯識二十論述記 2.41

2.41

述曰：次答不成，總有二頌，別破小乘。於中有二：初之二頌，破極微有合無合不成；後之一頌，破極微有分無分不成。就初段中，復分為二：初答合等不成；後結不成。答合等不成中，既有二頌，復分為二：初設答不成；後破救不成。初中二難，上之二句難極微合應成六分；下之二句難極微合應成六分，極微同處聚，應如極微，如阿拏色合七極微成。中有一極微，外邊有六，中極微若與外六極微合，所合既六，能合極微應成六分；若以極微更無分故，不相合者，六對之時，便相糅住，同一處所。既同一處，阿耨色等各各應如一極微量。

Commentary: Next is answering the untenability, consisting of two verses in total, specifically refuting the Hīnayāna. Herein there are two parts: the first two verses refute the untenability of atoms having conjunction or non-conjunction; the latter one verse refutes the untenability of atoms having parts or lacking parts. Within the first section, it is again divided into two: first, answering that conjunction and so forth are untenable; second, concluding the untenability. In answering that conjunction and so forth are untenable, since there are two verses, it is again divided into two: first, setting forth the answer of untenability; second, refuting the rescues as untenable. In the first part there are two difficulties: the upper two lines present the difficulty that if atoms conjoin, one should have six parts; the lower two lines present the difficulty that if atoms conjoin they would have six parts, and if atoms share the same location, an aggregate would be like an atom. Just as a particle of aṇu-form is formed by the conjunction of seven atoms: there is one atom in the middle and six on the outside; if the middle atom conjoins with the outer six atoms, since the conjoined are six, the conjoining atom should have six parts; if, because atoms have no further parts, they do not conjoin with each other, then when the six face it, they would merge and abide together in one and the same location. Since they are in the same location, the aṇu-forms and so on should each be equal in size to a single atom.