Book of Indian Eras, with Tables for Calculating Indian Dates c30.9

c30.9

The tables themselves are so clear and simple that they scarcely require any explanation. But suppose it be required to find the week day of the 20th October 1712 A.D. First look in Table III of the Julian Calendar for the year 1700 A.D., then run the eye down until it meets the horizontal line opposite of the year 12, and the intersection will show the initial day of the year 1712 as Tuesday. Next look in Table II at top for the horizontal line of week days, beginning with Tuesday, which is the third one of the seven, and as 1712 was a leap year, look for the name of October in the right hand column. Then, taking the 20th day of October, and running the eye upwards until it meets the horizontal line of week days, of which Tuesday was the 1st of January in that year, it will be seen that Monday was the 20th of October, as recorded at the head of the Spectator “Monday, October 20th, 1712.”