Mathematics in Ancient and Medieval India c6.s10.14
Mathematics in Ancient and Medieval India c6.s10.14
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c6.s10.14
Again circumradius of the triangle ABD = (b₁ c₂ × a₂ c₁)/(2a₂ b₁) = (c₁ c₂)/2
Mathematics in Ancient and Medieval India c6.s10.14
Again circumradius of the triangle ABD = (b₁ c₂ × a₂ c₁)/(2a₂ b₁) = (c₁ c₂)/2