Mathematics in Ancient and Medieval India c6.s5.22

c6.s5.22

Squaring both sides, and cancelling e₁² from both sides, we get $8/3e₁=2-16/9=2/9$ $₁=2/9×⅜=1/12=1/3.4$ $∴√2=1+⅓+1/3.4$ $Again let √2=1+⅓+1/3.4+e₂$ $=17/12+e₂$