Mathematics in Ancient and Medieval India c7.s5.190

c7.s5.190

(ii) Solution of : 67x² + 1 = y² We know, 67.1² - 3 = 8² . . . . . (1) Comparing with Na² + c = b², N = 67 a = 1, b = 8, c = -3. Now (am + b)/c = (1.m + 8)/(-3) = (m + 8)/(-3) is an integer when m = 7.