Mathematics in Ancient and Medieval India c7.s5.192

c7.s5.192

Hence, taking m=7 $a₁=(am+b)/c=(7+8)/(-3)=-5$ $b₁=(bm+Na)/c=(8.7+67)/(-3)=(56+67)/(-3)=123/(-3)=-41$ $c₁=(m²-N)/c=(49-67)/(-3)=(-18)/(-3)=6$ $∴ 67.(-5)²+6=(-41)⁸$ $or 67.5²+6=41². (2)$