Mathematics in Ancient and Medieval India c7.s5.199

c7.s5.199

From modern approach we know : \begin{align*} √67 &= 8 + 1/(5+) \ 1/(2+) \ 1/(\bar+) \ 1/(1+) \ 1/(7+) \ 1/(8+) \dots\dots\dots \\ &= 8, \ 41/5, \ 90/11, \ 221/27, \ 97684/11939 (= 48842/5967), \dots\dots\dots \end{align*}