Mathematics in Ancient and Medieval India c7.s5.207
Mathematics in Ancient and Medieval India c7.s5.207
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c7.s5.207
It, therefore, follows that : $N((ab¹¹b)/(√(KK¹)))² + 1 = ((bb¹¹)/(√(KK¹)))²$
Mathematics in Ancient and Medieval India c7.s5.207
It, therefore, follows that : $N((ab¹¹b)/(√(KK¹)))² + 1 = ((bb¹¹)/(√(KK¹)))²$