Mathematics in Ancient and Medieval India c7.s5.210

c7.s5.210

An anonymous scholar gave the rational solution of the equation Nx² + 1 = y² in the form : $x = k/(Bh-Ab), y = (Ah-Bb)/(Bh-Ab)$ where b, k, and h are respectively the base, upright and hypotenuse of a rightangled triangle; A, B being two numbers such that A² - B² = N.