Mathematics in Ancient and Medieval India c7.s5.70

Language: English

c7.s5.70

( 1 ) “What is that number which being divided by 12, leaves the remainder 5; again when divided by 31 has the remainder 7 ?” (*Āryabhaṭīya bhāṣya*). *Hints* : To solve N = 12x + 5 = 31y + 7. Here N = 317, x = 31, y = 10.

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Linked texts (1)

Mahābhāskarīya — Bhāskara I, Sanskrit