Mathematics in Ancient and Medieval India c8.113

c8.113

¹ Sin 2 A = 2 Sin A Cos A (ch. 3, v. 73); Sin 3 A = 3 Sin A – 4 Sin³A (ch. 3, v. 74); Sin (A±B) = Sin A Cos B±Cos A Sin B (ch. 3, v. 68); Cos (A±B) = Cos A Cos BSin A Sin B (ch. 3, v. 69); etc. [in modern equivalents.]