Mathematics in Ancient and Medieval India c8.126
Mathematics in Ancient and Medieval India c8.126
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c8.126
(3) i) In the right-angled triangle (Fig. 20) PMB, PM² + MB² = PB² or ½√(PM² + MB²) = ½ PB or ½√*Jyā*² A + *Utkramajyā*² A = *Jyā* A/2 (arc BP = A)