Mathematics in Ancient and Medieval India c8.136
Mathematics in Ancient and Medieval India c8.136
- Language
- English
c8.136
Again SB = ½ PB = √((2(R² + RJ))/2) = √((R² + RJ)/2)
Mathematics in Ancient and Medieval India c8.136
Again SB = ½ PB = √((2(R² + RJ))/2) = √((R² + RJ)/2)