Mathematics in Ancient and Medieval India c8.s3.47
Mathematics in Ancient and Medieval India c8.s3.47
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c8.s3.47
After this rational approximation, the series becomes, $(π)/4 = 1 - ⅓ + ⅕ - ± 1/n$ $(((n + 1)²)/4 + 1)/(( (n + 1)/2 ) [ (n + 1)² + 4 + 1 ])$