Mathematics in Ancient and Medieval India c9.24

c9.24

Now in the two similar triangles POQ and P₀TP $= (PP₀ × OQ)/OP = (A × R )/R = A$ From similar traingles PP₀T and PP₁S (chord PP₁ = PP₀, when the arc is very small) $P₁S = (P₀T × PP₁)/PP₀ = (A · (y'-y))/A = · (y'-y)$ or, ' - = · (y'-y) which is equivalent to or, d() = dy