The Science of the Shulba: A Study in Early Hindu Geometry c19.s1.2
The Science of the Śulba: A Study in Early Hindu Geometry c19.s1.2
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c19.s1.2
Putting m² for n, in order to make the sides of the right-angled triangle free from the radical, and dividing out by a² we get $m² + ( (m² - 1)/2 )² = ( (m² + 1)/2 )² I$ as the solution of the indeterminate equation of the second degree $x² + y² = z². A$