The Science of the Shulba: A Study in Early Hindu Geometry c20.s5.18
The Science of the Śulba: A Study in Early Hindu Geometry c20.s5.18
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c20.s5.18
Complete the larger square by adding a portion III which is deducted from r/(2a+1). Then the area of IV will be $= r/(2a+1) - (r / a+1)² = r/(2a+1)(1 - r/(2a+1)).$