The Science of the Shulba: A Study in Early Hindu Geometry c21.s2.8
The Science of the Śulba: A Study in Early Hindu Geometry c21.s2.8
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c21.s2.8
That is, $7½ square puruṣas =(3-⅓) puruṣas ²$ $+(½ puruṣa+10 aṅgulis )×(1-⅓) puruṣa;$ the right-hand side, in square puruṣas $=(2⅔)²+(½+1/12)(1-⅓),$ $=7 1/9+7/12×⅔,$ $=7½.$