The Science of the Shulba: A Study in Early Hindu Geometry c7.21

c7.21

So that the added portion a/m shall have to be divided into 2(m+1) parts. Then the *nirañchana* mark is to be made at a distance $a/m-a/m÷2(m+1)=a/m-a/(2m(m+1))=((2m+1)a)/(2m(m+1)).$