History of Hindu Mathematics: A Source Book v1.c8.s10.6
History of Hindu Mathematics: A Source Book v1.c8.s10.6
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v1.c8.s10.6
Then $n = d₁ + 10d₂ + + 10m-1d_m,$ $S₁ = d₁ + d₂ + d₃ + + d_m$ so that $n - S₁ = 9(d₂ + 11d₃ + ).$
History of Hindu Mathematics: A Source Book v1.c8.s10.6
Then $n = d₁ + 10d₂ + + 10m-1d_m,$ $S₁ = d₁ + d₂ + d₃ + + d_m$ so that $n - S₁ = 9(d₂ + 11d₃ + ).$