History of Hindu Mathematics: A Source Book v1.c8.s14.60

v1.c8.s14.60

² *GSS*, p. 55 (60). The problem gives the equation $(x-(x²)/12.30)-1.3/20.16(x-(x²)/12.30)²=20.$ Also solved by *regula falsi*. Mahâvîra puts (x-1/12.30x²)=z, and then solves the quadratic $z-3/320z²=20.$ The roots of this are then used to get the values of x.