History of Hindu Mathematics: A Source Book v2.c17.s10.38
History of Hindu Mathematics: A Source Book v2.c17.s10.38
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v2.c17.s10.38
*i.e.*, $x + y = √(2c - d²).$ Therefore $x = ½(√(2c - d²) + d), y = ½(√(2c - d²) - d).$
History of Hindu Mathematics: A Source Book v2.c17.s10.38
*i.e.*, $x + y = √(2c - d²).$ Therefore $x = ½(√(2c - d²) + d), y = ½(√(2c - d²) - d).$