History of Hindu Mathematics: A Source Book v2.c17.s14.135
History of Hindu Mathematics: A Source Book v2.c17.s14.135
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v2.c17.s14.135
Hence x=½αβ, y=½(β²-2); and x=½α(β²-1), y=½β(β²-3); are solutions of $Nx²+1=y².$
History of Hindu Mathematics: A Source Book v2.c17.s14.135
Hence x=½αβ, y=½(β²-2); and x=½α(β²-1), y=½β(β²-3); are solutions of $Nx²+1=y².$