History of Hindu Mathematics: A Source Book v2.c17.s14.140
History of Hindu Mathematics: A Source Book v2.c17.s14.140
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v2.c17.s14.140
The *rationale* of this solution is as follows : $Na² - 4 = β². 1$ $∴ N((α)/2)² - 1 = ((β)/2)².$
History of Hindu Mathematics: A Source Book v2.c17.s14.140
The *rationale* of this solution is as follows : $Na² - 4 = β². 1$ $∴ N((α)/2)² - 1 = ((β)/2)².$