History of Hindu Mathematics: A Source Book v2.c17.s14.142
History of Hindu Mathematics: A Source Book v2.c17.s14.142
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v2.c17.s14.142
Again, applying the Corollary, we have $N½αβ(β² + 2)² + 1 = ½(β⁴ + 4β² + 2)². 3$
History of Hindu Mathematics: A Source Book v2.c17.s14.142
Again, applying the Corollary, we have $N½αβ(β² + 2)² + 1 = ½(β⁴ + 4β² + 2)². 3$