History of Hindu Mathematics: A Source Book v2.c17.s14.69

v2.c17.s14.69

That is, suppose the Square-nature to be $Nx² ± p²d = y²,$ so that its interpolator p²d is exactly divisible by the square p². Then, putting therein u=x/p, v=y/p, we derive the equation $Nu² ± d = v²,$ whose interpolator is equal to that of the original Square-nature divided by p². It is clear that the roots of the original equation are p times those of the derived equation.