History of Hindu Mathematics: A Source Book v2.c17.s16.4
History of Hindu Mathematics: A Source Book v2.c17.s16.4
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v2.c17.s16.4
Eliminating n between $a₁ k = an + b, b₁ k = bn + Na,$ we get $a₁ b - ab₁ = 1.$
History of Hindu Mathematics: A Source Book v2.c17.s16.4
Eliminating n between $a₁ k = an + b, b₁ k = bn + Na,$ we get $a₁ b - ab₁ = 1.$