History of Hindu Mathematics: A Source Book v2.c17.s17.t1.14

v2.c17.s17.t1.14

Now suppose x = r, when z = m; that is, let m = ar + b/2. Substituting in the above expressions, we get the required solution of (1) as $. x &= 1/2a(bq - b) + qr ± lp, / y &= lq ± (apr + ½bp); 1.2$ where ap² + 1 = q² and ar² + br + c = l².