History of Hindu Mathematics: A Source Book v2.c17.s17.t2.15

v2.c17.s17.t2.15

Now, let l = ar + ½b and m = aa's + ½ab'. Substituting in the above expressions, we get the required solution of (2) in the form : $. x &= 1/2a(qb ± pab' - b) + qr ± pa's, / y &= 1/(2a')(qb' ± pa'b - b') + qs ± par ; (2.5)$ where aa'p² + 1 = q², and ar² + br + c = a's² + b's + c'.