History of Hindu Mathematics: A Source Book v2.c17.s17.t4.12
History of Hindu Mathematics: A Source Book v2.c17.s17.t4.12
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v2.c17.s17.t4.12
For, with this value, we have $z² &= (b²y⁴)/(4d²) + by² + d² / &= 1/(4d²) (by² + 2d²)².$
History of Hindu Mathematics: A Source Book v2.c17.s17.t4.12
For, with this value, we have $z² &= (b²y⁴)/(4d²) + by² + d² / &= 1/(4d²) (by² + 2d²)².$