History of Hindu Mathematics: A Source Book v2.c17.s17.t5.14

v2.c17.s17.t5.14

Now, if we suppose y = m/n, where m, n are arbitrary integers, we get the solution of (5.1) as x &= 1/(8\lambda p²n²) {m²(4cp² - b²) - 4\lambda² p²n² - 4\lambda bmn}, / y &= m/n, / z &= 1/(8\lambda p²n²) {m²(4cp² - b²) + 4\lambda² p²n²}.