History of Hindu Mathematics: A Source Book v2.c17.s18.t2.17

v2.c17.s18.t2.17

In other words, to solve (A), assume $y = s (ratio of perimeters)(ratio of areas)², (1)$ and x = y - 1, if p = q, \hfill (2) or x = 3 [y - s (ratio of areas) - 1], if p ≠ q, \hfill (2') where s is an arbitrary number, and the ratios are to be so presented as always to remain greater than or equal to unity.