History of Hindu Mathematics: A Source Book v2.c17.s19.22
History of Hindu Mathematics: A Source Book v2.c17.s19.22
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v2.c17.s19.22
From (1) and (2), we get $b'=(b+a)/2+(h²/r-r)/2, 4$ $a'=(b+a)/2-(h²/r-r)/2. 5$
History of Hindu Mathematics: A Source Book v2.c17.s19.22
From (1) and (2), we get $b'=(b+a)/2+(h²/r-r)/2, 4$ $a'=(b+a)/2-(h²/r-r)/2. 5$