History of Hindu Mathematics: A Source Book v2.c17.s19.26
History of Hindu Mathematics: A Source Book v2.c17.s19.26
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v2.c17.s19.26
Substituting these values in (2), (4), (5) we get the dimensions of the equivalent isosceles trapezium as $a' &= (p² - q²) - (4p²q²/r - r)/2, / b' &= (p² - q²) + (4p²q²/r - r)/2, / c' &= (4p²q²/r + r)/2.$