History of Hindu Mathematics: A Source Book v2.c17.s20.27

v2.c17.s20.27

With m = 1, n = 2 Nârâyaṇa gives the following sets of particular values : \begin{align*} (1.2) \enspace &x, y = 5/9, 10/9 & (4.2) \enspace &x, y = 5/27, 10/27 \\ (2.2) \enspace &x, y = 1, 2 & (5.2) \enspace &x, y = 1/3 2/3, \\ (3.2) \enspace &x, y = 2/9, 4/9 & (6.2) \enspace &x, y = 2/27, 4/27 \end{align*} He then observes : "In this way one can find by his own intelligence two numbers for the case of *difference*, etc."