History of Hindu Mathematics: A Source Book v2.c17.s21.15
History of Hindu Mathematics: A Source Book v2.c17.s21.15
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v2.c17.s21.15
*Case i.* Let *c* be a square, equal to β², say. Then we have to solve $bx + β² = y².$ The rule says, find *p* such that $p² = bq, 2pβ = br.$ Then assume $y = pu + β ;$ whence we get $x = qu² + ru.$