History of Hindu Mathematics: A Source Book v2.c17.s22.41

v2.c17.s22.41

If u = r, w = s be a solution of this transformed equation, another solution of it will be $u = rq ± ps,$ $w = qs ± abrp ;$ where abp² + 1 = q². Therefore, the general solution of (1) is $x = 1/a(rq ± ps)² - c/a,$ $u = rq ± ps,$ $v = 1/a(qs ± abrp) ;$ where abp² + 1 = q² and abr² + a²d - abc = s².