History of Hindu Mathematics: A Source Book v2.c17.s22.45

v2.c17.s22.45

Putting α = β = 1, t = a, and taking the positive sign only, we get a particular solution of the equations .ax + 1 = u² / bx + 1 = v²} as x = (8(a + b))/((a - b)²), u = (3a + b)/(a - b), v = (a + 3b)/(a - b).