History of Hindu Mathematics: A Source Book v2.c17.s23.15
History of Hindu Mathematics: A Source Book v2.c17.s23.15
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v2.c17.s23.15
Since $(p² + q²) ± 2pq$ is always a square, we may assume $x² = (p² + q²)w² 1,$ $y² = 2pqw².$
History of Hindu Mathematics: A Source Book v2.c17.s23.15
Since $(p² + q²) ± 2pq$ is always a square, we may assume $x² = (p² + q²)w² 1,$ $y² = 2pqw².$