History of Hindu Mathematics: A Source Book v2.c17.s23.23
History of Hindu Mathematics: A Source Book v2.c17.s23.23
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v2.c17.s23.23
In particular, put m = 2t, n = 1, r = 8t² - 1 in (A). Then, we get the solution . x &= 1/2((8t² - 1)/2t)² + 1, & u &= (64t⁴ - 1)/(8t²), / y &= (8t² - 1)/2t, & v &= 1/2((8t² - 1)/2t)². } (a)