History of Hindu Mathematics: A Source Book v2.c17.s23.56

v2.c17.s23.56

In the first equation suppose x = 2y; then u = 6y. Putting x = 2y, the second equation becomes $20y² + 1 = v².$ By the method of the Square-nature the values of y satisfying this equation are 2, 36, etc. Hence the solutions of the given double equation are $x = 4, 72, / y = 2, 36,$