History of Hindu Mathematics: A Source Book v2.c17.s23.6

v2.c17.s23.6

For the solution of (*i*) Bhâskara II assumes¹ $x² = 5z² - 1, y² = 4z²,$ so that both the equations are satisfied. Now, by the method of the Square-nature, the solutions of the equation 5z² - 1 = x² are (1, 2), (17, 38),...Therefore, the solutions of (*i*) are $.x &= 2 / y &= 2, .x &= 38 / y &= 34,$