History of Hindu Mathematics: A Source Book v2.c17.s25.26

v2.c17.s25.26

In particular, putting m = 1, n = 2, p = 10, Nârâyaṇa finds x = 12500, y = 10000. With other values of m, n, p he obtains the values (3165/16, 625/4), (62500/117, 250000/507), (15625/1872, 15625/2028); and observes: “thus by virtue of (the multiplicity of) the optional numbers many values can be found.”