History of Hindu Mathematics: A Source Book v2.c17.s25.36
History of Hindu Mathematics: A Source Book v2.c17.s25.36
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v2.c17.s25.36
Since x = p² - α, y = q² - α, we get $xy + β = (p² - α)(q² - α) + β$ $= (pq - α)² + β - α(q - p)².$
History of Hindu Mathematics: A Source Book v2.c17.s25.36
Since x = p² - α, y = q² - α, we get $xy + β = (p² - α)(q² - α) + β$ $= (pq - α)² + β - α(q - p)².$