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History of Hindu Mathematics: A Source Book v2.c17.s25.44

History of Hindu Mathematics: A Source Book v2.c17.s25.44

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v2.c17.s25.44

Thus we have $ξ = p(p ± γ) - α,$ $η = (p ± γ)(p ± 2γ) - α,$ $ζ = (p ± 2γ)(p ± 3γ) - α;$ as stated by Bhâskara II.