History of Hindu Mathematics: A Source Book v2.c17.s25.67

v2.c17.s25.67

That is to say, if x > y, we have to solve $x - y + 3 = u²,$ $x + y + 3 = v²,$ $x² - y² + 12 = s²,$ $x² + y² - 4 = t²,$ $½xy + y = p³,$ $u + v + s + t + p + 2 = q².$