History of Hindu Mathematics: A Source Book v2.c17.s25.80
History of Hindu Mathematics: A Source Book v2.c17.s25.80
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v2.c17.s25.80
That is to say, if x > y, we have to solve $[3]½(xy+y)+√(x²+y²)+√(x²-y²+8)$ $+√(x+y+2)+√(x-y+2)=q².$
History of Hindu Mathematics: A Source Book v2.c17.s25.80
That is to say, if x > y, we have to solve $[3]½(xy+y)+√(x²+y²)+√(x²-y²+8)$ $+√(x+y+2)+√(x-y+2)=q².$