History of Hindu Mathematics: A Source Book v2.c17.s7.37

v2.c17.s7.37

That is, we get the equations x + 4 + 5 &= 2(y + z - 4 - 5), / y + 4 + 6 &= 3(z + x - 4 - 6), / z + 5 + 6 &= 5(x + y - 5 - 6); or 2(x + y + z) - 3x &= 27, / 3(x + y + z) - 4y &= 40, / 5(x + y + z) - 6z &= 66; a particular case of the system (III). Substituting in (1), we get x = 7, y = 8, z = 9.