History of Hindu Mathematics: A Source Book v2.c17.s8.110
History of Hindu Mathematics: A Source Book v2.c17.s8.110
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v2.c17.s8.110
Thus $x = (b/a ± √((b/a - 4c)b/a))/2.$
History of Hindu Mathematics: A Source Book v2.c17.s8.110
Thus $x = (b/a ± √((b/a - 4c)b/a))/2.$